LeetCodeCheck Balanced StringCheck Balanced StringEasyStringSolution export function isBalanced(num: string): boolean { const n = num.length; let [even, odd] = [0, 0]; for (let i = 0; i < n; i++) { if (i % 2 === 0) { even += parseInt(num[i]); } else { odd += parseInt(num[i]); } } return even === odd; } Complexity Time: O(n)O(n)O(n) Space: O(1)O(1)O(1) LeetCodeCheck Balanced Stringhttps://leetcode.com/problems/check-balanced-string