export function numberOfPairs(nums1: number[], nums2: number[], k: number): number {
function isGoodPair(num1: number, num2: number) {
return num1 % (num2 * k) === 0;
}
return nums1.reduce(
(prev, num1) => prev + nums2.filter((num2) => isGoodPair(num1, num2)).length,
0,
);
}