Find the Power of K-Size Subarrays I
MediumArraySliding Window
Solution
export function resultsArray(nums: number[], k: number): number[] {
if (k === 1) {
return nums;
}
const n = nums.length;
const answer = [];
let [left, right] = [0, 1];
while (right < n) {
const isConsecutive = nums[right] - nums[right - 1] === 1;
if (!isConsecutive) {
while (left < right && left + k - 1 < n) {
answer.push(-1);
left += 1;
}
left = right;
} else if (right - left === k - 1) {
answer.push(nums[right]);
left += 1;
}
right += 1;
}
return answer;
}
Complexity
- Time:
- Space: