Check If All 1's Are at Least Length K Places Away
EasyArray
Solution
export function kLengthApart(nums: number[], k: number): boolean {
const n = nums.length;
const startIndex = nums.findIndex((num) => num === 1);
let prevIndex = startIndex;
let minApart = Number.MAX_SAFE_INTEGER;
for (let i = startIndex + 1; i < n; i++) {
if (nums[i] === 1) {
minApart = Math.min(minApart, i - prevIndex);
prevIndex = i;
}
}
return k < minApart;
}