LeetCodeTime Needed to Buy TicketsTime Needed to Buy TicketsEasyArrayQueueSimulationSolution export function timeRequiredToBuy(tickets: number[], k: number): number { let answer = 0; for (let i = 0; i < tickets.length; i++) { answer += Math.min(i <= k ? tickets[k] : tickets[k] - 1, tickets[i]); } return answer; }LeetCodeTime Needed to Buy Ticketshttps://leetcode.com/problems/time-needed-to-buy-tickets