Search in Rotated Sorted Array

MediumArrayBinary Search

Solution

export function search(nums: number[], target: number): number {
  const n = nums.length;
 
  let [start, end] = [0, n - 1];
  while (start <= end) {
    const mid = Math.floor((start + end) / 2);
    if (nums[mid] === target) {
      return mid;
    }
 
    if (nums[start] <= nums[mid]) {
      if (nums[start] <= target && target < nums[mid]) {
        end = mid - 1;
      } else {
        start = mid + 1;
      }
    } else {
      if (nums[mid] < target && target <= nums[end]) {
        start = mid + 1;
      } else {
        end = mid - 1;
      }
    }
  }
  return -1;
}