Search in Rotated Sorted Array
MediumArrayBinary Search
Solution
export function search(nums: number[], target: number): number {
const n = nums.length;
let [start, end] = [0, n - 1];
while (start <= end) {
const mid = Math.floor((start + end) / 2);
if (nums[mid] === target) {
return mid;
}
if (nums[start] <= nums[mid]) {
if (nums[start] <= target && target < nums[mid]) {
end = mid - 1;
} else {
start = mid + 1;
}
} else {
if (nums[mid] < target && target <= nums[end]) {
start = mid + 1;
} else {
end = mid - 1;
}
}
}
return -1;
}