Bitwise XOR of All Pairings
MediumArrayBit ManipulationBrainteaser
Solution
export function xorAllNums(nums1: number[], nums2: number[]): number {
const [m, n] = [nums1.length, nums2.length];
const xor1 = n % 2 === 0 ? 0 : nums1.reduce(xor, 0);
const xor2 = m % 2 === 0 ? 0 : nums2.reduce(xor, 0);
return xor1 ^ xor2;
}
function xor(a: number, b: number): number {
return a ^ b;
}
Complexity
- Time:
- Space: